Base | Representation |
---|---|
bin | 1000101111000000000… |
… | …0000000000001100011 |
3 | 112100022121202010211021 |
4 | 2023300000000001203 |
5 | 4424303141420003 |
6 | 152533504230311 |
7 | 13561341011416 |
oct | 2136000000143 |
9 | 470277663737 |
10 | 150055420003 |
11 | 58702411005 |
12 | 250b930b397 |
13 | 111c4bb4868 |
14 | 7396c99b7d |
15 | 3d838ca2bd |
hex | 22f0000063 |
150055420003 has 2 divisors, whose sum is σ = 150055420004. Its totient is φ = 150055420002.
The previous prime is 150055419887. The next prime is 150055420049. The reversal of 150055420003 is 300024550051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150055420003 - 213 = 150055411811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 150055420003.
It is not a weakly prime, because it can be changed into another prime (150055420093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027710001 + 75027710002.
It is an arithmetic number, because the mean of its divisors is an integer number (75027710002).
Almost surely, 2150055420003 is an apocalyptic number.
150055420003 is a deficient number, since it is larger than the sum of its proper divisors (1).
150055420003 is an equidigital number, since it uses as much as digits as its factorization.
150055420003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 25.
Adding to 150055420003 its reverse (300024550051), we get a palindrome (450079970054).
The spelling of 150055420003 in words is "one hundred fifty billion, fifty-five million, four hundred twenty thousand, three".
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