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15010999141 is a prime number
BaseRepresentation
bin11011111101011100…
…11010101101100101
31102202010211202200011
431332232122231211
5221220303433031
610521305450221
71040662246615
oct157656325545
942663752604
1015010999141
116403354916
122aab1a0971
131552bca618
14a25888a45
155ccc886b1
hex37eb9ab65

15010999141 has 2 divisors, whose sum is σ = 15010999142. Its totient is φ = 15010999140.

The previous prime is 15010999139. The next prime is 15010999177. The reversal of 15010999141 is 14199901051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10469587041 + 4541412100 = 102321^2 + 67390^2 .

It is a cyclic number.

It is not a de Polignac number, because 15010999141 - 21 = 15010999139 is a prime.

It is a super-2 number, since 2×150109991412 (a number of 21 digits) contains 22 as substring.

Together with 15010999139, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 15010999094 and 15010999103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15010991141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7505499570 + 7505499571.

It is an arithmetic number, because the mean of its divisors is an integer number (7505499571).

Almost surely, 215010999141 is an apocalyptic number.

It is an amenable number.

15010999141 is a deficient number, since it is larger than the sum of its proper divisors (1).

15010999141 is an equidigital number, since it uses as much as digits as its factorization.

15010999141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 40.

The spelling of 15010999141 in words is "fifteen billion, ten million, nine hundred ninety-nine thousand, one hundred forty-one".