Base | Representation |
---|---|
bin | 100010001010010011001010… |
… | …010111101110001111000111 |
3 | 201200221221012002101122002002 |
4 | 202022103022113232033013 |
5 | 124143023241403333112 |
6 | 1251311531322335515 |
7 | 43434402512312423 |
oct | 4212231227561707 |
9 | 650857162348062 |
10 | 150241351230407 |
11 | 43964aa9a92948 |
12 | 14a2594465a59b |
13 | 65aa910b71a58 |
14 | 2915a12323b83 |
15 | 12581c7cea1c2 |
hex | 88a4ca5ee3c7 |
150241351230407 has 2 divisors, whose sum is σ = 150241351230408. Its totient is φ = 150241351230406.
The previous prime is 150241351230307. The next prime is 150241351230419. The reversal of 150241351230407 is 704032153142051.
150241351230407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150241351230407 - 218 = 150241350968263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150241351230497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75120675615203 + 75120675615204.
It is an arithmetic number, because the mean of its divisors is an integer number (75120675615204).
Almost surely, 2150241351230407 is an apocalyptic number.
150241351230407 is a deficient number, since it is larger than the sum of its proper divisors (1).
150241351230407 is an equidigital number, since it uses as much as digits as its factorization.
150241351230407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
The spelling of 150241351230407 in words is "one hundred fifty trillion, two hundred forty-one billion, three hundred fifty-one million, two hundred thirty thousand, four hundred seven".
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