150314117 has 2 divisors, whose sum is σ = 150314118. Its totient is φ = 150314116.

The previous prime is 150314113. The next prime is 150314141. The reversal of 150314117 is 711413051.

It is a happy number.

150314117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 145781476 + 4532641 = 12074^2 + 2129^2 .

It is an emirp because it is prime and its reverse (711413051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150314117 - 2² = 150314113 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 150314092 and 150314101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150314113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75157058 + 75157059.

It is an arithmetic number, because the mean of its divisors is an integer number (75157059).

Almost surely, 2^150314117 is an apocalyptic number.

It is an amenable number.

150314117 is a deficient number, since it is larger than the sum of its proper divisors (1).

150314117 is an equidigital number, since it uses as much as digits as its factorization.

150314117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 23.

The square root of 150314117 is about 12260.2657801534. The cubic root of 150314117 is about 531.6999139114.

Adding to 150314117 its reverse (711413051), we get a palindrome (861727168).

The spelling of 150314117 in words is "one hundred fifty million, three hundred fourteen thousand, one hundred seventeen".