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150341207 is a prime number
BaseRepresentation
bin10001111011000…
…00011001010111
3101110220010100212
420331200121113
5301441404312
622530200035
73503610362
oct1075403127
9343803325
10150341207
1177955635
124242301b
13251bb2c3
1415d770d9
15d2ea822
hex8f60657

150341207 has 2 divisors, whose sum is σ = 150341208. Its totient is φ = 150341206.

The previous prime is 150341161. The next prime is 150341209. The reversal of 150341207 is 702143051.

150341207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (702143051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150341207 - 26 = 150341143 is a prime.

Together with 150341209, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150341209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75170603 + 75170604.

It is an arithmetic number, because the mean of its divisors is an integer number (75170604).

Almost surely, 2150341207 is an apocalyptic number.

150341207 is a deficient number, since it is larger than the sum of its proper divisors (1).

150341207 is an equidigital number, since it uses as much as digits as its factorization.

150341207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 150341207 is about 12261.3705188286. The cubic root of 150341207 is about 531.7318534385.

Adding to 150341207 its reverse (702143051), we get a palindrome (852484258).

The spelling of 150341207 in words is "one hundred fifty million, three hundred forty-one thousand, two hundred seven".