Base | Representation |
---|---|
bin | 100010001100101001000100… |
… | …011010000000110100101101 |
3 | 201201112022122202022100022021 |
4 | 202030221010122000310231 |
5 | 124203142413441104013 |
6 | 1251513511331550141 |
7 | 43452131340113314 |
oct | 4214510432006455 |
9 | 651468582270267 |
10 | 150402312441133 |
11 | 43a17298435935 |
12 | 14a50b8615b351 |
13 | 65bcb532b70cc |
14 | 291d72176927b |
15 | 125c498d55a8d |
hex | 88ca44680d2d |
150402312441133 has 2 divisors, whose sum is σ = 150402312441134. Its totient is φ = 150402312441132.
The previous prime is 150402312441079. The next prime is 150402312441257. The reversal of 150402312441133 is 331144213204051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 132875002688164 + 17527309752969 = 11527142^2 + 4186563^2 .
It is a cyclic number.
It is not a de Polignac number, because 150402312441133 - 29 = 150402312440621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150402312442133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75201156220566 + 75201156220567.
It is an arithmetic number, because the mean of its divisors is an integer number (75201156220567).
Almost surely, 2150402312441133 is an apocalyptic number.
It is an amenable number.
150402312441133 is a deficient number, since it is larger than the sum of its proper divisors (1).
150402312441133 is an equidigital number, since it uses as much as digits as its factorization.
150402312441133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 150402312441133 its reverse (331144213204051), we get a palindrome (481546525645184).
The spelling of 150402312441133 in words is "one hundred fifty trillion, four hundred two billion, three hundred twelve million, four hundred forty-one thousand, one hundred thirty-three".
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