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15040332133 is a prime number
BaseRepresentation
bin11100000000111100…
…10100000101100101
31102211012001000222021
432000132110011211
5221300311112013
610524234303141
71041466466551
oct160036240545
942735030867
1015040332133
11641896a162
122ab8b87ab1
131558ccab18
14a29722861
155d062ea8d
hex380794165

15040332133 has 2 divisors, whose sum is σ = 15040332134. Its totient is φ = 15040332132.

The previous prime is 15040332127. The next prime is 15040332137. The reversal of 15040332133 is 33123304051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11084299524 + 3956032609 = 105282^2 + 62897^2 .

It is a cyclic number.

It is not a de Polignac number, because 15040332133 - 217 = 15040201061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15040332098 and 15040332107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15040332137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520166066 + 7520166067.

It is an arithmetic number, because the mean of its divisors is an integer number (7520166067).

Almost surely, 215040332133 is an apocalyptic number.

It is an amenable number.

15040332133 is a deficient number, since it is larger than the sum of its proper divisors (1).

15040332133 is an equidigital number, since it uses as much as digits as its factorization.

15040332133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 15040332133 its reverse (33123304051), we get a palindrome (48163636184).

The spelling of 15040332133 in words is "fifteen billion, forty million, three hundred thirty-two thousand, one hundred thirty-three".