Base | Representation |
---|---|
bin | 100010001101001111111010… |
… | …001000111001000111101111 |
3 | 201201200022022011010100000212 |
4 | 202031033322020321013233 |
5 | 124204333321111041421 |
6 | 1251545005450213035 |
7 | 43455135652346021 |
oct | 4215177210710757 |
9 | 651608264110025 |
10 | 150444016112111 |
11 | 43a32a49034117 |
12 | 14a5908472417b |
13 | 65c3a6b2ccab7 |
14 | 292175a2d6011 |
15 | 125d5da1b8e5b |
hex | 88d3fa2391ef |
150444016112111 has 2 divisors, whose sum is σ = 150444016112112. Its totient is φ = 150444016112110.
The previous prime is 150444016112087. The next prime is 150444016112153. The reversal of 150444016112111 is 111211610444051.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150444016112111 is a prime.
It is a super-2 number, since 2×1504440161121112 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150444016112711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75222008056055 + 75222008056056.
It is an arithmetic number, because the mean of its divisors is an integer number (75222008056056).
Almost surely, 2150444016112111 is an apocalyptic number.
150444016112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
150444016112111 is an equidigital number, since it uses as much as digits as its factorization.
150444016112111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 32.
Adding to 150444016112111 its reverse (111211610444051), we get a palindrome (261655626556162).
The spelling of 150444016112111 in words is "one hundred fifty trillion, four hundred forty-four billion, sixteen million, one hundred twelve thousand, one hundred eleven".
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