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150444016112111 is a prime number
BaseRepresentation
bin100010001101001111111010…
…001000111001000111101111
3201201200022022011010100000212
4202031033322020321013233
5124204333321111041421
61251545005450213035
743455135652346021
oct4215177210710757
9651608264110025
10150444016112111
1143a32a49034117
1214a5908472417b
1365c3a6b2ccab7
14292175a2d6011
15125d5da1b8e5b
hex88d3fa2391ef

150444016112111 has 2 divisors, whose sum is σ = 150444016112112. Its totient is φ = 150444016112110.

The previous prime is 150444016112087. The next prime is 150444016112153. The reversal of 150444016112111 is 111211610444051.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150444016112111 is a prime.

It is a super-2 number, since 2×1504440161121112 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150444016112711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75222008056055 + 75222008056056.

It is an arithmetic number, because the mean of its divisors is an integer number (75222008056056).

Almost surely, 2150444016112111 is an apocalyptic number.

150444016112111 is a deficient number, since it is larger than the sum of its proper divisors (1).

150444016112111 is an equidigital number, since it uses as much as digits as its factorization.

150444016112111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 32.

Adding to 150444016112111 its reverse (111211610444051), we get a palindrome (261655626556162).

The spelling of 150444016112111 in words is "one hundred fifty trillion, four hundred forty-four billion, sixteen million, one hundred twelve thousand, one hundred eleven".