Base | Representation |
---|---|
bin | 1101101110111101011010… |
… | …0110010011110001100100 |
3 | 1222110120210120020211002121 |
4 | 3123233112212103301210 |
5 | 3434401120031142012 |
6 | 52041011025115324 |
7 | 3115653150463663 |
oct | 333572646236144 |
9 | 58416716224077 |
10 | 15100410412132 |
11 | 48a2059013361 |
12 | 183a688a88b44 |
13 | 856c68a77b26 |
14 | 3a2c1424adda |
15 | 1b2be291ca07 |
hex | dbbd6993c64 |
15100410412132 has 24 divisors (see below), whose sum is σ = 26459769278264. Its totient is φ = 7540480657152.
The previous prime is 15100410412121. The next prime is 15100410412177. The reversal of 15100410412132 is 23121401400151.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 5284821667876 + 9815588744256 = 2298874^2 + 3132984^2 .
It is a super-2 number, since 2×151004104121322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15100410412097 and 15100410412106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13487488 + ... + 14564104.
Almost surely, 215100410412132 is an apocalyptic number.
It is an amenable number.
15100410412132 is a deficient number, since it is larger than the sum of its proper divisors (11359358866132).
15100410412132 is a wasteful number, since it uses less digits than its factorization.
15100410412132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1081135 (or 1081133 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 15100410412132 its reverse (23121401400151), we get a palindrome (38221811812283).
The spelling of 15100410412132 in words is "fifteen trillion, one hundred billion, four hundred ten million, four hundred twelve thousand, one hundred thirty-two".
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