15113101 has 2 divisors, whose sum is σ = 15113102. Its totient is φ = 15113100.

The previous prime is 15113099. The next prime is 15113141. The reversal of 15113101 is 10131151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12257001 + 2856100 = 3501^2 + 1690^2 .

It is an emirp because it is prime and its reverse (10131151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15113101 - 2¹ = 15113099 is a prime.

Together with 15113099, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15113141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7556550 + 7556551.

It is an arithmetic number, because the mean of its divisors is an integer number (7556551).

Almost surely, 2^15113101 is an apocalyptic number.

It is an amenable number.

15113101 is a deficient number, since it is larger than the sum of its proper divisors (1).

15113101 is an equidigital number, since it uses as much as digits as its factorization.

15113101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 15113101 is about 3887.5572021515. The cubic root of 15113101 is about 247.2395028128.

Adding to 15113101 its reverse (10131151), we get a palindrome (25244252).

The spelling of 15113101 in words is "fifteen million, one hundred thirteen thousand, one hundred one".