Base | Representation |
---|---|
bin | 100010010111011100111110… |
… | …011101100010011001110111 |
3 | 201211011100021210102112012102 |
4 | 202113130332131202121313 |
5 | 124302330423430402043 |
6 | 1253243055435412315 |
7 | 43556611666414043 |
oct | 4227347635423167 |
9 | 654140253375172 |
10 | 151145242044023 |
11 | 44183378870587 |
12 | 14b50b638b409b |
13 | 6644c20740626 |
14 | 294767c35b023 |
15 | 127197bbd06b8 |
hex | 89773e762677 |
151145242044023 has 2 divisors, whose sum is σ = 151145242044024. Its totient is φ = 151145242044022.
The previous prime is 151145242044019. The next prime is 151145242044037. The reversal of 151145242044023 is 320440242541151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151145242044023 - 22 = 151145242044019 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151145242074023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75572621022011 + 75572621022012.
It is an arithmetic number, because the mean of its divisors is an integer number (75572621022012).
Almost surely, 2151145242044023 is an apocalyptic number.
151145242044023 is a deficient number, since it is larger than the sum of its proper divisors (1).
151145242044023 is an equidigital number, since it uses as much as digits as its factorization.
151145242044023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 151145242044023 its reverse (320440242541151), we get a palindrome (471585484585174).
The spelling of 151145242044023 in words is "one hundred fifty-one trillion, one hundred forty-five billion, two hundred forty-two million, forty-four thousand, twenty-three".
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