Base | Representation |
---|---|
bin | 1000110011010101110… |
… | …0101011010000001111 |
3 | 112110022211011122021221 |
4 | 2030311130223100033 |
5 | 4434144431040012 |
6 | 153245245304211 |
7 | 13632246410551 |
oct | 2146534532017 |
9 | 473284148257 |
10 | 151220565007 |
11 | 59150080766 |
12 | 25383565067 |
13 | 1134c3c4285 |
14 | 74679154d1 |
15 | 3e00d2d507 |
hex | 233572b40f |
151220565007 has 2 divisors, whose sum is σ = 151220565008. Its totient is φ = 151220565006.
The previous prime is 151220564977. The next prime is 151220565011. The reversal of 151220565007 is 700565022151.
151220565007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 151220565007 - 231 = 149073081359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151220565407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75610282503 + 75610282504.
It is an arithmetic number, because the mean of its divisors is an integer number (75610282504).
Almost surely, 2151220565007 is an apocalyptic number.
151220565007 is a deficient number, since it is larger than the sum of its proper divisors (1).
151220565007 is an equidigital number, since it uses as much as digits as its factorization.
151220565007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21000, while the sum is 34.
Adding to 151220565007 its reverse (700565022151), we get a palindrome (851785587158).
The spelling of 151220565007 in words is "one hundred fifty-one billion, two hundred twenty million, five hundred sixty-five thousand, seven".
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