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15130005493 is a prime number
BaseRepresentation
bin11100001011101000…
…11000111111110101
31110001102202220200211
432011310120333311
5221441240133433
610541200305421
71043635632121
oct160564307765
943042686624
1015130005493
116464548079
122b23012271
131571767195
14a375c6581
155d84448cd
hex385d18ff5

15130005493 has 2 divisors, whose sum is σ = 15130005494. Its totient is φ = 15130005492.

The previous prime is 15130005439. The next prime is 15130005557. The reversal of 15130005493 is 39450003151.

It is a happy number.

Together with previous prime (15130005439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14948241169 + 181764324 = 122263^2 + 13482^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15130005493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15130005433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7565002746 + 7565002747.

It is an arithmetic number, because the mean of its divisors is an integer number (7565002747).

Almost surely, 215130005493 is an apocalyptic number.

It is an amenable number.

15130005493 is a deficient number, since it is larger than the sum of its proper divisors (1).

15130005493 is an equidigital number, since it uses as much as digits as its factorization.

15130005493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 15130005493 in words is "fifteen billion, one hundred thirty million, five thousand, four hundred ninety-three".