Base | Representation |
---|---|
bin | 11100001100001011… |
… | …01001111000101101 |
3 | 1110001202021211200112 |
4 | 32012011221320231 |
5 | 221443414443432 |
6 | 10541441305405 |
7 | 1044022251266 |
oct | 160605517055 |
9 | 43052254615 |
10 | 15134531117 |
11 | 6467059262 |
12 | 2b24635265 |
13 | 1572690074 |
14 | a3804396d |
15 | 5d8a3a7b2 |
hex | 386169e2d |
15134531117 has 2 divisors, whose sum is σ = 15134531118. Its totient is φ = 15134531116.
The previous prime is 15134531099. The next prime is 15134531131. The reversal of 15134531117 is 71113543151.
15134531117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7824110116 + 7310421001 = 88454^2 + 85501^2 .
It is a cyclic number.
It is not a de Polignac number, because 15134531117 - 218 = 15134268973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15134591117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7567265558 + 7567265559.
It is an arithmetic number, because the mean of its divisors is an integer number (7567265559).
Almost surely, 215134531117 is an apocalyptic number.
It is an amenable number.
15134531117 is a deficient number, since it is larger than the sum of its proper divisors (1).
15134531117 is an equidigital number, since it uses as much as digits as its factorization.
15134531117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6300, while the sum is 32.
The spelling of 15134531117 in words is "fifteen billion, one hundred thirty-four million, five hundred thirty-one thousand, one hundred seventeen".
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