Search a number
-
+
15136253440 = 295711312477
BaseRepresentation
bin11100001100011000…
…01110011000000000
31110001212112100021021
432012030032120000
5221444340102230
610541542235224
71044043013530
oct160614163000
943055470237
1015136253440
116468025270
122b25125b14
131572b43ca9
14a383714c0
155d8c7ac7a
hex38630e600

15136253440 has 320 divisors, whose sum is σ = 46725009408. Its totient is φ = 4563763200.

The previous prime is 15136253437. The next prime is 15136253441. The reversal of 15136253440 is 4435263151.

It is a tau number, because it is divible by the number of its divisors (320).

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 15136253396 and 15136253405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15136253441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6109482 + ... + 6111958.

Almost surely, 215136253440 is an apocalyptic number.

15136253440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 15136253440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23362504704).

15136253440 is an abundant number, since it is smaller than the sum of its proper divisors (31588755968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

15136253440 is a wasteful number, since it uses less digits than its factorization.

15136253440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2549 (or 2533 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 34.

The spelling of 15136253440 in words is "fifteen billion, one hundred thirty-six million, two hundred fifty-three thousand, four hundred forty".