1514083934381 has 2 divisors, whose sum is σ = 1514083934382. Its totient is φ = 1514083934380.

The previous prime is 1514083934357. The next prime is 1514083934383. The reversal of 1514083934381 is 1834393804151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1239806533156 + 274277401225 = 1113466^2 + 523715^2 .

It is a cyclic number.

It is not a de Polignac number, because 1514083934381 - 2²² = 1514079740077 is a prime.

It is a super-2 number, since 2×1514083934381² (a number of 25 digits) contains 22 as substring.

Together with 1514083934383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1514083934383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 757041967190 + 757041967191.

It is an arithmetic number, because the mean of its divisors is an integer number (757041967191).

Almost surely, 2^{1514083934381} is an apocalyptic number.

It is an amenable number.

1514083934381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1514083934381 is an equidigital number, since it uses as much as digits as its factorization.

1514083934381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1244160, while the sum is 50.

The spelling of 1514083934381 in words is "one trillion, five hundred fourteen billion, eighty-three million, nine hundred thirty-four thousand, three hundred eighty-one".