Base | Representation |
---|---|
bin | 100010011011011001100111… |
… | …001011011101111101100111 |
3 | 201212010021110210101121100111 |
4 | 202123121213023131331213 |
5 | 124321302002034101433 |
6 | 1254011441124553451 |
7 | 43615324140100126 |
oct | 4233314713357547 |
9 | 655107423347314 |
10 | 151416508112743 |
11 | 44278420455a35 |
12 | 14b9564a252887 |
13 | 6664691591923 |
14 | 2956853261abd |
15 | 1278a569a1dcd |
hex | 89b6672ddf67 |
151416508112743 has 2 divisors, whose sum is σ = 151416508112744. Its totient is φ = 151416508112742.
The previous prime is 151416508112741. The next prime is 151416508112773. The reversal of 151416508112743 is 347211805614151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151416508112743 - 21 = 151416508112741 is a prime.
Together with 151416508112741, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151416508112741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75708254056371 + 75708254056372.
It is an arithmetic number, because the mean of its divisors is an integer number (75708254056372).
Almost surely, 2151416508112743 is an apocalyptic number.
151416508112743 is a deficient number, since it is larger than the sum of its proper divisors (1).
151416508112743 is an equidigital number, since it uses as much as digits as its factorization.
151416508112743 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 806400, while the sum is 49.
The spelling of 151416508112743 in words is "one hundred fifty-one trillion, four hundred sixteen billion, five hundred eight million, one hundred twelve thousand, seven hundred forty-three".
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