Base | Representation |
---|---|
bin | 1000110100011111101… |
… | …0110111100111010111 |
3 | 112111010102022102210222 |
4 | 2031013322313213113 |
5 | 4440313300013342 |
6 | 153340115504555 |
7 | 13643031512321 |
oct | 2150772674727 |
9 | 474112272728 |
10 | 151530469847 |
11 | 59299aaa869 |
12 | 2544b2b815b |
13 | 1139b67c513 |
14 | 7496b46611 |
15 | 3e1d146ed2 |
hex | 2347eb79d7 |
151530469847 has 2 divisors, whose sum is σ = 151530469848. Its totient is φ = 151530469846.
The previous prime is 151530469841. The next prime is 151530469913. The reversal of 151530469847 is 748964035151.
It is a weak prime.
It is an emirp because it is prime and its reverse (748964035151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151530469847 - 214 = 151530453463 is a prime.
It is a super-2 number, since 2×1515304698472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151530469841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75765234923 + 75765234924.
It is an arithmetic number, because the mean of its divisors is an integer number (75765234924).
Almost surely, 2151530469847 is an apocalyptic number.
151530469847 is a deficient number, since it is larger than the sum of its proper divisors (1).
151530469847 is an equidigital number, since it uses as much as digits as its factorization.
151530469847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 53.
The spelling of 151530469847 in words is "one hundred fifty-one billion, five hundred thirty million, four hundred sixty-nine thousand, eight hundred forty-seven".
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