Base | Representation |
---|---|
bin | 10010000111000… |
… | …11011001000111 |
3 | 101120212122202121 |
4 | 21003203121013 |
5 | 302343120333 |
6 | 23024150411 |
7 | 3523231642 |
oct | 1103433107 |
9 | 346778677 |
10 | 151926343 |
11 | 78838568 |
12 | 42a68407 |
13 | 2562495a |
14 | 1626aa59 |
15 | d51032d |
hex | 90e3647 |
151926343 has 2 divisors, whose sum is σ = 151926344. Its totient is φ = 151926342.
The previous prime is 151926317. The next prime is 151926349. The reversal of 151926343 is 343629151.
It is a strong prime.
It is an emirp because it is prime and its reverse (343629151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151926343 - 217 = 151795271 is a prime.
It is a super-2 number, since 2×1519263432 = 46163227394707298, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 151926299 and 151926308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151926349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75963171 + 75963172.
It is an arithmetic number, because the mean of its divisors is an integer number (75963172).
Almost surely, 2151926343 is an apocalyptic number.
151926343 is a deficient number, since it is larger than the sum of its proper divisors (1).
151926343 is an equidigital number, since it uses as much as digits as its factorization.
151926343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19440, while the sum is 34.
The square root of 151926343 is about 12325.8404581594. The cubic root of 151926343 is about 533.5941112283.
The spelling of 151926343 in words is "one hundred fifty-one million, nine hundred twenty-six thousand, three hundred forty-three".
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