Base | Representation |
---|---|
bin | 10110000111101000011… |
… | …101001110010101101101 |
3 | 12101022110001020210120221 |
4 | 112013220131032111231 |
5 | 144401001444234014 |
6 | 3122142241211341 |
7 | 214550411656663 |
oct | 26075035162555 |
9 | 5338401223527 |
10 | 1520023430509 |
11 | 536702666071 |
12 | 206710930b51 |
13 | b0450905c3c |
14 | 537d8ad0c33 |
15 | 298151e2b24 |
hex | 161e874e56d |
1520023430509 has 2 divisors, whose sum is σ = 1520023430510. Its totient is φ = 1520023430508.
The previous prime is 1520023430467. The next prime is 1520023430531. The reversal of 1520023430509 is 9050343200251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1127890728484 + 392132702025 = 1062022^2 + 626205^2 .
It is an emirp because it is prime and its reverse (9050343200251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1520023430509 - 215 = 1520023397741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1520023430599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760011715254 + 760011715255.
It is an arithmetic number, because the mean of its divisors is an integer number (760011715255).
Almost surely, 21520023430509 is an apocalyptic number.
It is an amenable number.
1520023430509 is a deficient number, since it is larger than the sum of its proper divisors (1).
1520023430509 is an equidigital number, since it uses as much as digits as its factorization.
1520023430509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 1520023430509 in words is "one trillion, five hundred twenty billion, twenty-three million, four hundred thirty thousand, five hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •