Base | Representation |
---|---|
bin | 11100010100001111… |
… | …00010110101111111 |
3 | 1110020110111111100201 |
4 | 32022013202311333 |
5 | 222113221313143 |
6 | 10552254304331 |
7 | 1045503006346 |
oct | 161207426577 |
9 | 43213444321 |
10 | 15202135423 |
11 | 64a1233392 |
12 | 2b431b80a7 |
13 | 15836a0307 |
14 | a43000b5d |
15 | 5de94164d |
hex | 38a1e2d7f |
15202135423 has 2 divisors, whose sum is σ = 15202135424. Its totient is φ = 15202135422.
The previous prime is 15202135411. The next prime is 15202135451. The reversal of 15202135423 is 32453120251.
It is an a-pointer prime, because the next prime (15202135451) can be obtained adding 15202135423 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15202135423 - 29 = 15202134911 is a prime.
It is a super-2 number, since 2×152021354232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15202135391 and 15202135400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15202135483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7601067711 + 7601067712.
It is an arithmetic number, because the mean of its divisors is an integer number (7601067712).
Almost surely, 215202135423 is an apocalyptic number.
15202135423 is a deficient number, since it is larger than the sum of its proper divisors (1).
15202135423 is an equidigital number, since it uses as much as digits as its factorization.
15202135423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 15202135423 its reverse (32453120251), we get a palindrome (47655255674).
The spelling of 15202135423 in words is "fifteen billion, two hundred two million, one hundred thirty-five thousand, four hundred twenty-three".
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