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152034504200503 is a prime number
BaseRepresentation
bin100010100100011001001010…
…100111011101000100110111
3201221022100122000001122021121
4202210121022213131010313
5124411413131033404003
61255203404221524411
744011062513134251
oct4244311247350467
9657270560048247
10152034504200503
11444965200a9631
121507537ba13707
1366aaa3b6aca72
14297871b5d4cd1
151289b766a3cbd
hex8a464a9dd137

152034504200503 has 2 divisors, whose sum is σ = 152034504200504. Its totient is φ = 152034504200502.

The previous prime is 152034504200483. The next prime is 152034504200521. The reversal of 152034504200503 is 305002405430251.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152034504200503 is a prime.

It is a super-3 number, since 3×1520345042005033 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152034504200533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76017252100251 + 76017252100252.

It is an arithmetic number, because the mean of its divisors is an integer number (76017252100252).

Almost surely, 2152034504200503 is an apocalyptic number.

152034504200503 is a deficient number, since it is larger than the sum of its proper divisors (1).

152034504200503 is an equidigital number, since it uses as much as digits as its factorization.

152034504200503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 152034504200503 its reverse (305002405430251), we get a palindrome (457036909630754).

The spelling of 152034504200503 in words is "one hundred fifty-two trillion, thirty-four billion, five hundred four million, two hundred thousand, five hundred three".