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15205304113 is a prime number
BaseRepresentation
bin11100010100100111…
…01000011100110001
31110020200110110222121
432022103220130301
5222120024212423
610552450234241
71045541644456
oct161223503461
943220413877
1015205304113
1164a2aa803a
122b44285981
13158423c68c
14a435c782d
155ded6a45d
hex38a4e8731

15205304113 has 2 divisors, whose sum is σ = 15205304114. Its totient is φ = 15205304112.

The previous prime is 15205304053. The next prime is 15205304137. The reversal of 15205304113 is 31140350251.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14745973489 + 459330624 = 121433^2 + 21432^2 .

It is an emirp because it is prime and its reverse (31140350251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15205304113 - 29 = 15205303601 is a prime.

It is not a weakly prime, because it can be changed into another prime (15205305113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7602652056 + 7602652057.

It is an arithmetic number, because the mean of its divisors is an integer number (7602652057).

Almost surely, 215205304113 is an apocalyptic number.

It is an amenable number.

15205304113 is a deficient number, since it is larger than the sum of its proper divisors (1).

15205304113 is an equidigital number, since it uses as much as digits as its factorization.

15205304113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 15205304113 its reverse (31140350251), we get a palindrome (46345654364).

The spelling of 15205304113 in words is "fifteen billion, two hundred five million, three hundred four thousand, one hundred thirteen".