Base | Representation |
---|---|
bin | 11100010101000001… |
… | …01000011111001111 |
3 | 1110020220212121220221 |
4 | 32022200220133033 |
5 | 222121412242033 |
6 | 10553051252211 |
7 | 1045612630432 |
oct | 161240503717 |
9 | 43226777827 |
10 | 15208712143 |
11 | 64a4a15599 |
12 | 2b4544a067 |
13 | 1584b63971 |
14 | a43c33819 |
15 | 5e02e012d |
hex | 38a8287cf |
15208712143 has 2 divisors, whose sum is σ = 15208712144. Its totient is φ = 15208712142.
The previous prime is 15208712131. The next prime is 15208712213. The reversal of 15208712143 is 34121780251.
15208712143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15208712143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15208712099 and 15208712108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15208782143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7604356071 + 7604356072.
It is an arithmetic number, because the mean of its divisors is an integer number (7604356072).
Almost surely, 215208712143 is an apocalyptic number.
15208712143 is a deficient number, since it is larger than the sum of its proper divisors (1).
15208712143 is an equidigital number, since it uses as much as digits as its factorization.
15208712143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 34.
The spelling of 15208712143 in words is "fifteen billion, two hundred eight million, seven hundred twelve thousand, one hundred forty-three".
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