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152112244541 is a prime number
BaseRepresentation
bin1000110110101010011…
…0001010011100111101
3112112121222000122122212
42031222212022130331
54443011213311131
6153513541150205
713663324513415
oct2155246123475
9475558018585
10152112244541
115956843a7a4
12255920bb365
13114620666ba
147510107645
153e54264a2b
hex236a98a73d

152112244541 has 2 divisors, whose sum is σ = 152112244542. Its totient is φ = 152112244540.

The previous prime is 152112244523. The next prime is 152112244549. The reversal of 152112244541 is 145442211251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106029035641 + 46083208900 = 325621^2 + 214670^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152112244541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 152112244498 and 152112244507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152112244549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76056122270 + 76056122271.

It is an arithmetic number, because the mean of its divisors is an integer number (76056122271).

Almost surely, 2152112244541 is an apocalyptic number.

It is an amenable number.

152112244541 is a deficient number, since it is larger than the sum of its proper divisors (1).

152112244541 is an equidigital number, since it uses as much as digits as its factorization.

152112244541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12800, while the sum is 32.

Adding to 152112244541 its reverse (145442211251), we get a palindrome (297554455792).

The spelling of 152112244541 in words is "one hundred fifty-two billion, one hundred twelve million, two hundred forty-four thousand, five hundred forty-one".