Base | Representation |
---|---|
bin | 1000110110101101011… |
… | …1011001101100100101 |
3 | 112112122212022102102021 |
4 | 2031223113121230211 |
5 | 4443023014331122 |
6 | 153515121543141 |
7 | 13663542312535 |
oct | 2155327315445 |
9 | 475585272367 |
10 | 152125152037 |
11 | 59574756351 |
12 | 255964a4ab1 |
13 | 11464935781 |
14 | 7511b074c5 |
15 | 3e554641c7 |
hex | 236b5d9b25 |
152125152037 has 2 divisors, whose sum is σ = 152125152038. Its totient is φ = 152125152036.
The previous prime is 152125151999. The next prime is 152125152097. The reversal of 152125152037 is 730251521251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78024690241 + 74100461796 = 279329^2 + 272214^2 .
It is a cyclic number.
It is not a de Polignac number, because 152125152037 - 215 = 152125119269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 152125151993 and 152125152011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152125152097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76062576018 + 76062576019.
It is an arithmetic number, because the mean of its divisors is an integer number (76062576019).
Almost surely, 2152125152037 is an apocalyptic number.
It is an amenable number.
152125152037 is a deficient number, since it is larger than the sum of its proper divisors (1).
152125152037 is an equidigital number, since it uses as much as digits as its factorization.
152125152037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21000, while the sum is 34.
Adding to 152125152037 its reverse (730251521251), we get a palindrome (882376673288).
The spelling of 152125152037 in words is "one hundred fifty-two billion, one hundred twenty-five million, one hundred fifty-two thousand, thirty-seven".
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