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152142510511 is a prime number
BaseRepresentation
bin1000110110110001100…
…1100111100110101111
3112112201001222022202201
42031230121213212233
54443041440314021
6153520542002331
713664143000405
oct2155431474657
9475631868681
10152142510511
1159583531aa2
12255a02763a7
1311468402764
147514145475
153e56c42591
hex236c6679af

152142510511 has 2 divisors, whose sum is σ = 152142510512. Its totient is φ = 152142510510.

The previous prime is 152142510449. The next prime is 152142510539. The reversal of 152142510511 is 115015241251.

It is an a-pointer prime, because the next prime (152142510539) can be obtained adding 152142510511 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 152142510511 - 29 = 152142509999 is a prime.

It is a super-2 number, since 2×1521425105112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 152142510511.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152142517511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76071255255 + 76071255256.

It is an arithmetic number, because the mean of its divisors is an integer number (76071255256).

Almost surely, 2152142510511 is an apocalyptic number.

152142510511 is a deficient number, since it is larger than the sum of its proper divisors (1).

152142510511 is an equidigital number, since it uses as much as digits as its factorization.

152142510511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2000, while the sum is 28.

Adding to 152142510511 its reverse (115015241251), we get a palindrome (267157751762).

The spelling of 152142510511 in words is "one hundred fifty-two billion, one hundred forty-two million, five hundred ten thousand, five hundred eleven".