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152142510551 = 314907822921
BaseRepresentation
bin1000110110110001100…
…1100111100111010111
3112112201001222022211012
42031230121213213113
54443041440314201
6153520542002435
713664143000463
oct2155431474727
9475631868735
10152142510551
1159583532029
12255a027641b
1311468402795
1475141454a3
153e56c425bb
hex236c6679d7

152142510551 has 4 divisors (see below), whose sum is σ = 157050333504. Its totient is φ = 147234687600.

The previous prime is 152142510547. The next prime is 152142510631. The reversal of 152142510551 is 155015241251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 152142510551 - 22 = 152142510547 is a prime.

It is a super-2 number, since 2×1521425105512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152142510511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2453911430 + ... + 2453911491.

It is an arithmetic number, because the mean of its divisors is an integer number (39262583376).

Almost surely, 2152142510551 is an apocalyptic number.

152142510551 is a deficient number, since it is larger than the sum of its proper divisors (4907822953).

152142510551 is an equidigital number, since it uses as much as digits as its factorization.

152142510551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4907822952.

The product of its (nonzero) digits is 10000, while the sum is 32.

The spelling of 152142510551 in words is "one hundred fifty-two billion, one hundred forty-two million, five hundred ten thousand, five hundred fifty-one".

Divisors: 1 31 4907822921 152142510551