Base | Representation |
---|---|
bin | 1000110110110001100… |
… | …1100111100111010111 |
3 | 112112201001222022211012 |
4 | 2031230121213213113 |
5 | 4443041440314201 |
6 | 153520542002435 |
7 | 13664143000463 |
oct | 2155431474727 |
9 | 475631868735 |
10 | 152142510551 |
11 | 59583532029 |
12 | 255a027641b |
13 | 11468402795 |
14 | 75141454a3 |
15 | 3e56c425bb |
hex | 236c6679d7 |
152142510551 has 4 divisors (see below), whose sum is σ = 157050333504. Its totient is φ = 147234687600.
The previous prime is 152142510547. The next prime is 152142510631. The reversal of 152142510551 is 155015241251.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 152142510551 - 22 = 152142510547 is a prime.
It is a super-2 number, since 2×1521425105512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152142510511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2453911430 + ... + 2453911491.
It is an arithmetic number, because the mean of its divisors is an integer number (39262583376).
Almost surely, 2152142510551 is an apocalyptic number.
152142510551 is a deficient number, since it is larger than the sum of its proper divisors (4907822953).
152142510551 is an equidigital number, since it uses as much as digits as its factorization.
152142510551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4907822952.
The product of its (nonzero) digits is 10000, while the sum is 32.
The spelling of 152142510551 in words is "one hundred fifty-two billion, one hundred forty-two million, five hundred ten thousand, five hundred fifty-one".
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