Base | Representation |
---|---|
bin | 100010100101111110110100… |
… | …111001010000011011101111 |
3 | 201221200210101100122200011222 |
4 | 202211332310321100123233 |
5 | 124420210204311401412 |
6 | 1255325455544133555 |
7 | 44022005522253263 |
oct | 4245766471203357 |
9 | 657623340580158 |
10 | 152143661434607 |
11 | 445288455591a7 |
12 | 150925644672bb |
13 | 66b811640230b |
14 | 297db148ba0a3 |
15 | 128c9147c8072 |
hex | 8a5fb4e506ef |
152143661434607 has 2 divisors, whose sum is σ = 152143661434608. Its totient is φ = 152143661434606.
The previous prime is 152143661434579. The next prime is 152143661434627. The reversal of 152143661434607 is 706434166341251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152143661434607 - 212 = 152143661430511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152143661434627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76071830717303 + 76071830717304.
It is an arithmetic number, because the mean of its divisors is an integer number (76071830717304).
Almost surely, 2152143661434607 is an apocalyptic number.
152143661434607 is a deficient number, since it is larger than the sum of its proper divisors (1).
152143661434607 is an equidigital number, since it uses as much as digits as its factorization.
152143661434607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8709120, while the sum is 53.
The spelling of 152143661434607 in words is "one hundred fifty-two trillion, one hundred forty-three billion, six hundred sixty-one million, four hundred thirty-four thousand, six hundred seven".
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