Base | Representation |
---|---|
bin | 11100010111100100… |
… | …10011011000010101 |
3 | 1110022102011100000211 |
4 | 32023302103120111 |
5 | 222142402341433 |
6 | 10555134205421 |
7 | 1046262616366 |
oct | 161362233025 |
9 | 43272140024 |
10 | 15230121493 |
11 | 6506008774 |
12 | 2b50653871 |
13 | 158941b712 |
14 | a46a07b6d |
15 | 5e211d8cd |
hex | 38bc93615 |
15230121493 has 2 divisors, whose sum is σ = 15230121494. Its totient is φ = 15230121492.
The previous prime is 15230121481. The next prime is 15230121521. The reversal of 15230121493 is 39412103251.
15230121493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12264012049 + 2966109444 = 110743^2 + 54462^2 .
It is a cyclic number.
It is not a de Polignac number, because 15230121493 - 233 = 6640186901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15230121433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7615060746 + 7615060747.
It is an arithmetic number, because the mean of its divisors is an integer number (7615060747).
Almost surely, 215230121493 is an apocalyptic number.
It is an amenable number.
15230121493 is a deficient number, since it is larger than the sum of its proper divisors (1).
15230121493 is an equidigital number, since it uses as much as digits as its factorization.
15230121493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 15230121493 in words is "fifteen billion, two hundred thirty million, one hundred twenty-one thousand, four hundred ninety-three".
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