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152333345117 is a prime number
BaseRepresentation
bin1000110111011111000…
…1100110000101011101
3112120012101001201122002
42031313301212011131
54443434314020432
6153551520132045
714001651032462
oct2156761460535
9476171051562
10152333345117
1159671224948
1225634167025
1311498acb045
14753161d669
153e6888ae62
hex2377c6615d

152333345117 has 2 divisors, whose sum is σ = 152333345118. Its totient is φ = 152333345116.

The previous prime is 152333345113. The next prime is 152333345149. The reversal of 152333345117 is 711543333251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134156643076 + 18176702041 = 366274^2 + 134821^2 .

It is an emirp because it is prime and its reverse (711543333251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 152333345117 - 22 = 152333345113 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152333345113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76166672558 + 76166672559.

It is an arithmetic number, because the mean of its divisors is an integer number (76166672559).

Almost surely, 2152333345117 is an apocalyptic number.

It is an amenable number.

152333345117 is a deficient number, since it is larger than the sum of its proper divisors (1).

152333345117 is an equidigital number, since it uses as much as digits as its factorization.

152333345117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 113400, while the sum is 38.

Adding to 152333345117 its reverse (711543333251), we get a palindrome (863876678368).

The spelling of 152333345117 in words is "one hundred fifty-two billion, three hundred thirty-three million, three hundred forty-five thousand, one hundred seventeen".