Base | Representation |
---|---|
bin | 1000111000001010000… |
… | …0000111111000011101 |
3 | 112120122220201002222121 |
4 | 2032002200013320131 |
5 | 4444321402024313 |
6 | 154021425342541 |
7 | 14006264532202 |
oct | 2160240077035 |
9 | 476586632877 |
10 | 152513314333 |
11 | 59753876436 |
12 | 25684497a51 |
13 | 114c7190bc3 |
14 | 754b4a9ca9 |
15 | 3e7958a28d |
hex | 2382807e1d |
152513314333 has 2 divisors, whose sum is σ = 152513314334. Its totient is φ = 152513314332.
The previous prime is 152513314243. The next prime is 152513314337. The reversal of 152513314333 is 333413315251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 152207659044 + 305655289 = 390138^2 + 17483^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-152513314333 is a prime.
It is a super-2 number, since 2×1525133143332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152513314337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76256657166 + 76256657167.
It is an arithmetic number, because the mean of its divisors is an integer number (76256657167).
Almost surely, 2152513314333 is an apocalyptic number.
It is an amenable number.
152513314333 is a deficient number, since it is larger than the sum of its proper divisors (1).
152513314333 is an equidigital number, since it uses as much as digits as its factorization.
152513314333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48600, while the sum is 34.
Adding to 152513314333 its reverse (333413315251), we get a palindrome (485926629584).
The spelling of 152513314333 in words is "one hundred fifty-two billion, five hundred thirteen million, three hundred fourteen thousand, three hundred thirty-three".
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