Base | Representation |
---|---|
bin | 10110010001011010011… |
… | …011100110001010001011 |
3 | 12102022112221211021211021 |
4 | 112101122123212022023 |
5 | 200034004014303003 |
6 | 3131040322013311 |
7 | 215401564305634 |
oct | 26213233461213 |
9 | 5368487737737 |
10 | 1530525541003 |
11 | 540101849128 |
12 | 208761aa7237 |
13 | b1435636cc4 |
14 | 541137d888b |
15 | 29c2c1d42bd |
hex | 1645a6e628b |
1530525541003 has 2 divisors, whose sum is σ = 1530525541004. Its totient is φ = 1530525541002.
The previous prime is 1530525540977. The next prime is 1530525541037. The reversal of 1530525541003 is 3001455250351.
It is an a-pointer prime, because the next prime (1530525541037) can be obtained adding 1530525541003 to its sum of digits (34).
It is a weak prime.
It is an emirp because it is prime and its reverse (3001455250351) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1530525541003 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1530525541003.
It is not a weakly prime, because it can be changed into another prime (1530525541603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765262770501 + 765262770502.
It is an arithmetic number, because the mean of its divisors is an integer number (765262770502).
Almost surely, 21530525541003 is an apocalyptic number.
1530525541003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1530525541003 is an equidigital number, since it uses as much as digits as its factorization.
1530525541003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 34.
The spelling of 1530525541003 in words is "one trillion, five hundred thirty billion, five hundred twenty-five million, five hundred forty-one thousand, three".
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