Base | Representation |
---|---|
bin | 1000111010010101111… |
… | …0100101011010010101 |
3 | 112122011210212121012012 |
4 | 2032211132211122111 |
5 | 10002022112113212 |
6 | 154155550434005 |
7 | 14026651331126 |
oct | 2164536453225 |
9 | 478153777165 |
10 | 153100113557 |
11 | 59a25028376 |
12 | 25808b02905 |
13 | 1158b917091 |
14 | 75a53b804d |
15 | 3eb0d4b922 |
hex | 23a57a5695 |
153100113557 has 2 divisors, whose sum is σ = 153100113558. Its totient is φ = 153100113556.
The previous prime is 153100113521. The next prime is 153100113577. The reversal of 153100113557 is 755311001351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132870456196 + 20229657361 = 364514^2 + 142231^2 .
It is a cyclic number.
It is not a de Polignac number, because 153100113557 - 210 = 153100112533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153100113577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76550056778 + 76550056779.
It is an arithmetic number, because the mean of its divisors is an integer number (76550056779).
Almost surely, 2153100113557 is an apocalyptic number.
It is an amenable number.
153100113557 is a deficient number, since it is larger than the sum of its proper divisors (1).
153100113557 is an equidigital number, since it uses as much as digits as its factorization.
153100113557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7875, while the sum is 32.
The spelling of 153100113557 in words is "one hundred fifty-three billion, one hundred million, one hundred thirteen thousand, five hundred fifty-seven".
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