Base | Representation |
---|---|
bin | 1101111011010010001111… |
… | …0110111001111111111110 |
3 | 2000012211100202110201111112 |
4 | 3132310203312321333332 |
5 | 4001333300430144032 |
6 | 52322150441522022 |
7 | 3140160412362056 |
oct | 336644366717776 |
9 | 60184322421445 |
10 | 15312160006142 |
11 | 497393a15542a |
12 | 18737234a3312 |
13 | 870c133a639c |
14 | 3ad1809a6566 |
15 | 1b848764d1b2 |
hex | ded23db9ffe |
15312160006142 has 32 divisors (see below), whose sum is σ = 24217884768000. Its totient is φ = 7240901542848.
The previous prime is 15312160006141. The next prime is 15312160006151. The reversal of 15312160006142 is 24160006121351.
It is a junction number, because it is equal to n+sod(n) for n = 15312160006099 and 15312160006108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15312160006141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54776933 + ... + 55055759.
It is an arithmetic number, because the mean of its divisors is an integer number (756808899000).
Almost surely, 215312160006142 is an apocalyptic number.
15312160006142 is a deficient number, since it is larger than the sum of its proper divisors (8905724761858).
15312160006142 is a wasteful number, since it uses less digits than its factorization.
15312160006142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 281280.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 15312160006142 its reverse (24160006121351), we get a palindrome (39472166127493).
The spelling of 15312160006142 in words is "fifteen trillion, three hundred twelve billion, one hundred sixty million, six thousand, one hundred forty-two".
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