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15313022141 is a prime number
BaseRepresentation
bin11100100001011101…
…00010110010111101
31110112012011010100012
432100232202302331
5222330113202031
611011255113005
71051320353264
oct162056426275
943465133305
1015313022141
1165488901aa
122b74372765
1315a0656161
14a53a275db
155e9546b2b
hex390ba2cbd

15313022141 has 2 divisors, whose sum is σ = 15313022142. Its totient is φ = 15313022140.

The previous prime is 15313022129. The next prime is 15313022143. The reversal of 15313022141 is 14122031351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12830092900 + 2482929241 = 113270^2 + 49829^2 .

It is a cyclic number.

It is not a de Polignac number, because 15313022141 - 26 = 15313022077 is a prime.

Together with 15313022143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15313022143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7656511070 + 7656511071.

It is an arithmetic number, because the mean of its divisors is an integer number (7656511071).

Almost surely, 215313022141 is an apocalyptic number.

It is an amenable number.

15313022141 is a deficient number, since it is larger than the sum of its proper divisors (1).

15313022141 is an equidigital number, since it uses as much as digits as its factorization.

15313022141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 15313022141 its reverse (14122031351), we get a palindrome (29435053492).

The spelling of 15313022141 in words is "fifteen billion, three hundred thirteen million, twenty-two thousand, one hundred forty-one".