Base | Representation |
---|---|
bin | 10010010000100… |
… | …11010001100001 |
3 | 101200012220011112 |
4 | 21020103101201 |
5 | 303202433131 |
6 | 23110553105 |
7 | 3536634542 |
oct | 1110232141 |
9 | 350186145 |
10 | 153171041 |
11 | 79508741 |
12 | 43368795 |
13 | 2596c36a |
14 | 164b24c9 |
15 | d6a902b |
hex | 9213461 |
153171041 has 2 divisors, whose sum is σ = 153171042. Its totient is φ = 153171040.
The previous prime is 153170977. The next prime is 153171043. The reversal of 153171041 is 140171351.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110334016 + 42837025 = 10504^2 + 6545^2 .
It is a cyclic number.
It is not a de Polignac number, because 153171041 - 26 = 153170977 is a prime.
It is a super-2 number, since 2×1531710412 = 46922735602047362, which contains 22 as substring.
Together with 153171043, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 153170998 and 153171016.
It is not a weakly prime, because it can be changed into another prime (153171043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76585520 + 76585521.
It is an arithmetic number, because the mean of its divisors is an integer number (76585521).
Almost surely, 2153171041 is an apocalyptic number.
It is an amenable number.
153171041 is a deficient number, since it is larger than the sum of its proper divisors (1).
153171041 is an equidigital number, since it uses as much as digits as its factorization.
153171041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 23.
The square root of 153171041 is about 12376.2288682781. The cubic root of 153171041 is about 535.0473548208.
The spelling of 153171041 in words is "one hundred fifty-three million, one hundred seventy-one thousand, forty-one".
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