Base | Representation |
---|---|
bin | 100010111000010010001100… |
… | …110111001010000000101111 |
3 | 202010011000212101021201021121 |
4 | 202320102030313022000233 |
5 | 130101312044243304403 |
6 | 1302131345352441411 |
7 | 44211613034055301 |
oct | 4270221467120057 |
9 | 663130771251247 |
10 | 153401415213103 |
11 | 449731a17a2942 |
12 | 1525627b6a9267 |
13 | 67798cac81245 |
14 | 29c494d427971 |
15 | 12b04c99193bd |
hex | 8b848cdca02f |
153401415213103 has 2 divisors, whose sum is σ = 153401415213104. Its totient is φ = 153401415213102.
The previous prime is 153401415213077. The next prime is 153401415213127. The reversal of 153401415213103 is 301312514104351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 153401415213103 - 237 = 153263976259631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153401415213173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76700707606551 + 76700707606552.
It is an arithmetic number, because the mean of its divisors is an integer number (76700707606552).
Almost surely, 2153401415213103 is an apocalyptic number.
153401415213103 is a deficient number, since it is larger than the sum of its proper divisors (1).
153401415213103 is an equidigital number, since it uses as much as digits as its factorization.
153401415213103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 153401415213103 its reverse (301312514104351), we get a palindrome (454713929317454).
The spelling of 153401415213103 in words is "one hundred fifty-three trillion, four hundred one billion, four hundred fifteen million, two hundred thirteen thousand, one hundred three".
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