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1534112034134 = 25359392436901
BaseRepresentation
bin10110010100110000001…
…100111110110101010110
312102122210220110000111012
4112110300030332311112
5200113330140043014
63132432241012222
7215556504064061
oct26246014766526
95378726400435
101534112034134
11541682281539
122093a3024072
13b18876982a4
1454373c6d8d8
1529d8bec8c3e
hex1653033ed56

1534112034134 has 16 divisors (see below), whose sum is σ = 2344982056560. Its totient is φ = 752456234400.

The previous prime is 1534112034109. The next prime is 1534112034211. The reversal of 1534112034134 is 4314302114351.

It is a super-2 number, since 2×15341120341342 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1534112034134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 588917 + ... + 1847984.

It is an arithmetic number, because the mean of its divisors is an integer number (146561378535).

Almost surely, 21534112034134 is an apocalyptic number.

1534112034134 is a deficient number, since it is larger than the sum of its proper divisors (810870022426).

1534112034134 is a wasteful number, since it uses less digits than its factorization.

1534112034134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2442895.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1534112034134 its reverse (4314302114351), we get a palindrome (5848414148485).

The spelling of 1534112034134 in words is "one trillion, five hundred thirty-four billion, one hundred twelve million, thirty-four thousand, one hundred thirty-four".

Divisors: 1 2 53 106 5939 11878 314767 629534 2436901 4873802 129155753 258311506 14472755039 28945510078 767056017067 1534112034134