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15343421 is a prime number
BaseRepresentation
bin111010100001…
…111100111101
31001212112012212
4322201330331
512411442141
61304510205
7244263002
oct72417475
931775185
1015343421
11872a815
12517b365
133242a62
1420758a9
1515312eb
hexea1f3d

15343421 has 2 divisors, whose sum is σ = 15343422. Its totient is φ = 15343420.

The previous prime is 15343417. The next prime is 15343423. The reversal of 15343421 is 12434351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15319396 + 24025 = 3914^2 + 155^2 .

It is an emirp because it is prime and its reverse (12434351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15343421 - 22 = 15343417 is a prime.

Together with 15343423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15343423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671710 + 7671711.

It is an arithmetic number, because the mean of its divisors is an integer number (7671711).

Almost surely, 215343421 is an apocalyptic number.

It is an amenable number.

15343421 is a deficient number, since it is larger than the sum of its proper divisors (1).

15343421 is an equidigital number, since it uses as much as digits as its factorization.

15343421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 23.

The square root of 15343421 is about 3917.0679085255. The cubic root of 15343421 is about 248.4891328492.

Adding to 15343421 its reverse (12434351), we get a palindrome (27777772).

The spelling of 15343421 in words is "fifteen million, three hundred forty-three thousand, four hundred twenty-one".