Base | Representation |
---|---|
bin | 100010111000111000000111… |
… | …101110100001110101001000 |
3 | 202010021220221221200221001112 |
4 | 202320320013232201311020 |
5 | 130102443441100121400 |
6 | 1302202201510505452 |
7 | 44214554024521526 |
oct | 4270700756416510 |
9 | 663256857627045 |
10 | 153442131254600 |
11 | 44989495957511 |
12 | 15262143365288 |
13 | 67806b949b5a6 |
14 | 29c68d2b47316 |
15 | 12b15ae1e1835 |
hex | 8b8e07ba1d48 |
153442131254600 has 192 divisors, whose sum is σ = 361862702586000. Its totient is φ = 60502966272000.
The previous prime is 153442131254597. The next prime is 153442131254609. The reversal of 153442131254600 is 6452131244351.
It can be written as a sum of positive squares in 24 ways, for example, as 35291274897316 + 118150856357284 = 5940646^2 + 10869722^2 .
It is not an unprimeable number, because it can be changed into a prime (153442131254609) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 18801874520 + ... + 18801882680.
Almost surely, 2153442131254600 is an apocalyptic number.
153442131254600 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 153442131254600, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180931351293000).
153442131254600 is an abundant number, since it is smaller than the sum of its proper divisors (208420571331400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
153442131254600 is a wasteful number, since it uses less digits than its factorization.
153442131254600 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12004 (or 11995 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 153442131254600 its reverse (6452131244351), we get a palindrome (159894262498951).
The spelling of 153442131254600 in words is "one hundred fifty-three trillion, four hundred forty-two billion, one hundred thirty-one million, two hundred fifty-four thousand, six hundred".
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