Search a number
-
+
1535241120143 is a prime number
BaseRepresentation
bin10110010101110011100…
…000000110100110001111
312102202201121000112022112
4112111303200012212033
5200123133211321033
63133140253134235
7215626464131033
oct26256340064617
95382647015275
101535241120143
11542101652575
1220965918a37b
13b1a07590c13
145443dbc01c3
1529e061a7c48
hex1657380698f

1535241120143 has 2 divisors, whose sum is σ = 1535241120144. Its totient is φ = 1535241120142.

The previous prime is 1535241120121. The next prime is 1535241120157. The reversal of 1535241120143 is 3410211425351.

It is a strong prime.

It is an emirp because it is prime and its reverse (3410211425351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1535241120143 - 212 = 1535241116047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1535241120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767620560071 + 767620560072.

It is an arithmetic number, because the mean of its divisors is an integer number (767620560072).

Almost surely, 21535241120143 is an apocalyptic number.

1535241120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1535241120143 is an equidigital number, since it uses as much as digits as its factorization.

1535241120143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1535241120143 its reverse (3410211425351), we get a palindrome (4945452545494).

The spelling of 1535241120143 in words is "one trillion, five hundred thirty-five billion, two hundred forty-one million, one hundred twenty thousand, one hundred forty-three".