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15354740021 is a prime number
BaseRepresentation
bin11100100110011011…
…01011110100110101
31110122002122121111212
432103031223310311
5222421303140041
611015345211205
71052335064615
oct162315536465
943562577455
1015354740021
11656a394495
122b86330b05
1315a91a18aa
14a593a6a45
155ed0378eb
hex39336bd35

15354740021 has 2 divisors, whose sum is σ = 15354740022. Its totient is φ = 15354740020.

The previous prime is 15354739987. The next prime is 15354740077. The reversal of 15354740021 is 12004745351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14905723921 + 449016100 = 122089^2 + 21190^2 .

It is an emirp because it is prime and its reverse (12004745351) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15354740021 is a prime.

It is a super-2 number, since 2×153547400212 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 15354740021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15354746021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7677370010 + 7677370011.

It is an arithmetic number, because the mean of its divisors is an integer number (7677370011).

Almost surely, 215354740021 is an apocalyptic number.

It is an amenable number.

15354740021 is a deficient number, since it is larger than the sum of its proper divisors (1).

15354740021 is an equidigital number, since it uses as much as digits as its factorization.

15354740021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 32.

The spelling of 15354740021 in words is "fifteen billion, three hundred fifty-four million, seven hundred forty thousand, twenty-one".