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154025013313 is a prime number
BaseRepresentation
bin1000111101110010011…
…0110011000001000001
3112201120021020101010201
42033130212303001001
510010420400411223
6154431430325201
714061612003643
oct2173446630101
9481507211121
10154025013313
115a35a117236
1225a267b9801
13116a841b142
147652176893
154017145ead
hex23dc9b3041

154025013313 has 2 divisors, whose sum is σ = 154025013314. Its totient is φ = 154025013312.

The previous prime is 154025013271. The next prime is 154025013341. The reversal of 154025013313 is 313310520451.

It is a happy number.

It is an a-pointer prime, because the next prime (154025013341) can be obtained adding 154025013313 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 152238091329 + 1786921984 = 390177^2 + 42272^2 .

It is a cyclic number.

It is not a de Polignac number, because 154025013313 - 217 = 154024882241 is a prime.

It is not a weakly prime, because it can be changed into another prime (154025013413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77012506656 + 77012506657.

It is an arithmetic number, because the mean of its divisors is an integer number (77012506657).

Almost surely, 2154025013313 is an apocalyptic number.

It is an amenable number.

154025013313 is a deficient number, since it is larger than the sum of its proper divisors (1).

154025013313 is an equidigital number, since it uses as much as digits as its factorization.

154025013313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 154025013313 its reverse (313310520451), we get a palindrome (467335533764).

The spelling of 154025013313 in words is "one hundred fifty-four billion, twenty-five million, thirteen thousand, three hundred thirteen".