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154054041013 is a prime number
BaseRepresentation
bin1000111101111001010…
…1100001110110110101
3112201122021212010122201
42033132111201312311
510011000313303023
6154434344424501
714062413512545
oct2173625416665
9481567763581
10154054041013
115a374543174
1225a34478131
13116b14426b2
147655d71325
15401997bbad
hex23de561db5

154054041013 has 2 divisors, whose sum is σ = 154054041014. Its totient is φ = 154054041012.

The previous prime is 154054040957. The next prime is 154054041041. The reversal of 154054041013 is 310140450451.

It is an a-pointer prime, because the next prime (154054041041) can be obtained adding 154054041013 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 145845318609 + 8208722404 = 381897^2 + 90602^2 .

It is a cyclic number.

It is not a de Polignac number, because 154054041013 - 221 = 154051943861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154054041313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77027020506 + 77027020507.

It is an arithmetic number, because the mean of its divisors is an integer number (77027020507).

Almost surely, 2154054041013 is an apocalyptic number.

It is an amenable number.

154054041013 is a deficient number, since it is larger than the sum of its proper divisors (1).

154054041013 is an equidigital number, since it uses as much as digits as its factorization.

154054041013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 154054041013 its reverse (310140450451), we get a palindrome (464194491464).

The spelling of 154054041013 in words is "one hundred fifty-four billion, fifty-four million, forty-one thousand, thirteen".