Base | Representation |
---|---|
bin | 10110011011011000001… |
… | …011010011110100101111 |
3 | 12110100011122000000001111 |
4 | 112123120023103310233 |
5 | 200222412113313112 |
6 | 3140010135252451 |
7 | 216230665332466 |
oct | 26333013236457 |
9 | 5410148000044 |
10 | 1541225135407 |
11 | 5446a2455831 |
12 | 20a84921a127 |
13 | b244c251059 |
14 | 5484a82b9dd |
15 | 2a1566d45a7 |
hex | 166d82d3d2f |
1541225135407 has 2 divisors, whose sum is σ = 1541225135408. Its totient is φ = 1541225135406.
The previous prime is 1541225135389. The next prime is 1541225135449. The reversal of 1541225135407 is 7045315221451.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1541225135407 - 211 = 1541225133359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1541225135407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1541225139407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770612567703 + 770612567704.
It is an arithmetic number, because the mean of its divisors is an integer number (770612567704).
Almost surely, 21541225135407 is an apocalyptic number.
1541225135407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541225135407 is an equidigital number, since it uses as much as digits as its factorization.
1541225135407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168000, while the sum is 40.
The spelling of 1541225135407 in words is "one trillion, five hundred forty-one billion, two hundred twenty-five million, one hundred thirty-five thousand, four hundred seven".
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