Base | Representation |
---|---|
bin | 1000111110100110001… |
… | …0111101110000011111 |
3 | 112202010101202011021221 |
4 | 2033221202331300133 |
5 | 10011341440100133 |
6 | 154505143434211 |
7 | 14100156216211 |
oct | 2175142756037 |
9 | 482111664257 |
10 | 154242112543 |
11 | 5a460719092 |
12 | 25a87455967 |
13 | 117113b141c |
14 | 7672d2a5b1 |
15 | 402b22ba2d |
hex | 23e98bdc1f |
154242112543 has 2 divisors, whose sum is σ = 154242112544. Its totient is φ = 154242112542.
The previous prime is 154242112483. The next prime is 154242112553. The reversal of 154242112543 is 345211242451.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-154242112543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 154242112499 and 154242112508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (154242112553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77121056271 + 77121056272.
It is an arithmetic number, because the mean of its divisors is an integer number (77121056272).
Almost surely, 2154242112543 is an apocalyptic number.
154242112543 is a deficient number, since it is larger than the sum of its proper divisors (1).
154242112543 is an equidigital number, since it uses as much as digits as its factorization.
154242112543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 38400, while the sum is 34.
Adding to 154242112543 its reverse (345211242451), we get a palindrome (499453354994).
The spelling of 154242112543 in words is "one hundred fifty-four billion, two hundred forty-two million, one hundred twelve thousand, five hundred forty-three".
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