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154404042551021 is a prime number
BaseRepresentation
bin100011000110110111111110…
…000110111010111011101101
3202020200212211012111201211102
4203012313332012322323231
5130214223434343113041
61304220123220132445
744344216053605534
oct4306677606727355
9666625735451742
10154404042551021
114521a42879568a
1215398655537125
1368203146720b3
142a1b2a478b31b
1512cb60bb6109b
hex8c6dfe1baeed

154404042551021 has 2 divisors, whose sum is σ = 154404042551022. Its totient is φ = 154404042551020.

The previous prime is 154404042551009. The next prime is 154404042551039. The reversal of 154404042551021 is 120155240404451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137684080660996 + 16719961890025 = 11733886^2 + 4089005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154404042551021 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154404072551021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77202021275510 + 77202021275511.

It is an arithmetic number, because the mean of its divisors is an integer number (77202021275511).

Almost surely, 2154404042551021 is an apocalyptic number.

It is an amenable number.

154404042551021 is a deficient number, since it is larger than the sum of its proper divisors (1).

154404042551021 is an equidigital number, since it uses as much as digits as its factorization.

154404042551021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128000, while the sum is 38.

Adding to 154404042551021 its reverse (120155240404451), we get a palindrome (274559282955472).

The spelling of 154404042551021 in words is "one hundred fifty-four trillion, four hundred four billion, forty-two million, five hundred fifty-one thousand, twenty-one".