Base | Representation |
---|---|
bin | 100011001111100011010100… |
… | …011000110001000001110101 |
3 | 202022210212222102002011102021 |
4 | 203033203110120301001311 |
5 | 130304011200304240432 |
6 | 1305354101413113141 |
7 | 44435255665254511 |
oct | 4317432430610165 |
9 | 668725872064367 |
10 | 155000343040117 |
11 | 4542a304882953 |
12 | 154741313287b1 |
13 | 6864614a1a4a3 |
14 | 2a3c0b157b141 |
15 | 12dbdabd12697 |
hex | 8cf8d4631075 |
155000343040117 has 2 divisors, whose sum is σ = 155000343040118. Its totient is φ = 155000343040116.
The previous prime is 155000343040063. The next prime is 155000343040159. The reversal of 155000343040117 is 711040343000551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 145132112432241 + 9868230607876 = 12047079^2 + 3141374^2 .
It is a cyclic number.
It is not a de Polignac number, because 155000343040117 - 27 = 155000343039989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155000343040177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77500171520058 + 77500171520059.
It is an arithmetic number, because the mean of its divisors is an integer number (77500171520059).
Almost surely, 2155000343040117 is an apocalyptic number.
It is an amenable number.
155000343040117 is a deficient number, since it is larger than the sum of its proper divisors (1).
155000343040117 is an equidigital number, since it uses as much as digits as its factorization.
155000343040117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 155000343040117 its reverse (711040343000551), we get a palindrome (866040686040668).
The spelling of 155000343040117 in words is "one hundred fifty-five trillion, three hundred forty-three million, forty thousand, one hundred seventeen".
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