Base | Representation |
---|---|
bin | 10110100011100100000… |
… | …011011111100100011111 |
3 | 12111011212011110020111012 |
4 | 112203210003133210133 |
5 | 200343412133110201 |
6 | 3144022230445435 |
7 | 216661541365625 |
oct | 26434403374437 |
9 | 5434764406435 |
10 | 1550014347551 |
11 | 5483a2765a1a |
12 | 2104a080387b |
13 | b322013a9b7 |
14 | 55041c53515 |
15 | 2a4bd1255bb |
hex | 168e40df91f |
1550014347551 has 2 divisors, whose sum is σ = 1550014347552. Its totient is φ = 1550014347550.
The previous prime is 1550014347509. The next prime is 1550014347619. The reversal of 1550014347551 is 1557434100551.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1550014347551 - 222 = 1550010153247 is a prime.
It is a super-2 number, since 2×15500143475512 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1550014347499 and 1550014347508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1550014349551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775007173775 + 775007173776.
It is an arithmetic number, because the mean of its divisors is an integer number (775007173776).
Almost surely, 21550014347551 is an apocalyptic number.
1550014347551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1550014347551 is an equidigital number, since it uses as much as digits as its factorization.
1550014347551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 210000, while the sum is 41.
The spelling of 1550014347551 in words is "one trillion, five hundred fifty billion, fourteen million, three hundred forty-seven thousand, five hundred fifty-one".
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